Solving the Equation: (2x+1)^2 - 3(x-5)^2 = (x+3)(x-3)
This article will guide you through the process of solving the equation (2x+1)^2 - 3(x-5)^2 = (x+3)(x-3).
Expanding the Equation
The first step is to expand the squares and the product on both sides of the equation.
- Left side:
- (2x+1)^2 = (2x+1)(2x+1) = 4x^2 + 4x + 1
- 3(x-5)^2 = 3(x-5)(x-5) = 3(x^2 -10x + 25) = 3x^2 - 30x + 75
- Right side:
- (x+3)(x-3) = x^2 - 9
Substituting these expanded forms into the original equation gives us:
4x^2 + 4x + 1 - (3x^2 - 30x + 75) = x^2 - 9
Simplifying and Solving
Now, we simplify the equation by combining like terms:
4x^2 + 4x + 1 - 3x^2 + 30x - 75 = x^2 - 9
x^2 + 34x - 74 = x^2 - 9
Further simplification leads to:
34x - 74 = -9
34x = 65
x = 65/34
Solution
Therefore, the solution to the equation (2x+1)^2 - 3(x-5)^2 = (x+3)(x-3) is x = 65/34.